4.9x^2-50x+80=0

Solution for 4.9x^2-50x+80=0 equation:

4.9x^2-50x+80=0

a = 4.9; b = -50; c = +80;
Δ = b2-4ac
Δ = -502-4·4.9·80
Δ = 932
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{932}=\sqrt{4*233}=\sqrt{4}*\sqrt{233}=2\sqrt{233}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{233}}{2*4.9}=\frac{50-2\sqrt{233}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{233}}{2*4.9}=\frac{50+2\sqrt{233}}{9.8}
$